Find the derivative of x^3 * sin(x)
- Two factors, so use the product rule
- Differentiate each part
- Put it together
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A derivative is a slope: how fast the output moves when the input nudges. Four rules cover almost everything you will be asked to differentiate, and the skill is spotting which shape you are looking at before you start.
Read the function from the outside in. The outermost operation decides the first rule you apply.
Bring the exponent down, subtract one from it. The derivative of xⁿ is n·xⁿ⁻¹, and it works for negative and fractional powers too.
Two things multiplied: first times the derivative of the second, plus second times the derivative of the first.
A fraction: (bottom × derivative of top − top × derivative of bottom) ÷ bottom squared. The order of that subtraction matters.
A function inside another: differentiate the outside, leave the inside alone, then multiply by the derivative of the inside. This is the one that gets forgotten.
When y is tangled up with x, differentiate both sides with respect to x, remembering that every y term picks up a dy/dx, then solve for dy/dx.
Each one is solved the way the solver solves it: the rule first, then the line.
Asked here and worked through in full. Open one for every step.
The derivative of sin(3x) is 3cos(3x), not cos(3x). The chain rule’s multiplier is the most commonly dropped factor in calculus.
Bottom times derivative of top comes first. Swapping the order flips the sign of the whole answer.
The derivative of 2ˣ is 2ˣ ln 2, not x·2ˣ⁻¹. The power rule needs the variable in the base, not the exponent.
The rate at which a function is changing, and the slope of its graph at a point. If distance is the function, the derivative is speed.
Apply the rule that matches the shape. The power rule drops the exponent to the front and lowers it by one, so the derivative of x³ is 3x²; products, quotients and compositions have their own rules.
For a function inside another function, differentiate the outside and multiply by the derivative of the inside. The derivative of (3x + 1)⁵ is 5(3x + 1)⁴ × 3.
For two functions multiplied together, the derivative is the first times the derivative of the second plus the second times the derivative of the first. For x³ sin x it is x³ cos x + 3x² sin x.
For a fraction, take the bottom times the derivative of the top, minus the top times the derivative of the bottom, all over the bottom squared.
Differentiate first, then substitute the value. For f(x) = 2x² − 3x + 1, the derivative is 4x − 3, so f′(2) = 5.
Differentiating both sides when y is not written alone, treating y as a function of x and attaching dy/dx by the chain rule each time y is differentiated.
Yes. Every step is labelled with the rule by name, so you can see where the chain rule was applied rather than only the final expression.