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Factor 2x^2 + 7x + 3

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Answer
(2x+1)(x+3)\boxed{(2x + 1)(x + 3)}

Multiplying the factors back together using FOIL confirms they equal the original expression 2x2+7x+32x^2 + 7x + 3.

Problem: Factor the quadratic expression 2x2+7x+32x^2 + 7x + 3.

Steps

  1. Find two numbers that multiply to 23=62 \cdot 3 = 6 and add up to 77
    The numbers are 6 and 1\text{The numbers are } 6 \text{ and } 1
  2. Split the middle term using these two numbers
    2x2+6x+x+32x^2 + 6x + x + 3
  3. Factor by grouping
    2x(x+3)+1(x+3)2x(x + 3) + 1(x + 3)
  4. Factor out the common binomial (x+3)(x + 3)
    (2x+1)(x+3)(2x + 1)(x + 3)

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