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Solve x^2 + 4x - 5 = 0

Worked through step by step. More quadratics.

Answer
x=−5,1\boxed{x = -5, 1}

Substituting x=1x = 1 back into the original equation gives 12+4(1)−5=01^2 + 4(1) - 5 = 0, which is correct.

Problem: Solve the quadratic equation x2+4x−5=0x^2 + 4x - 5 = 0.

Steps

  1. Factor the quadratic expression
    (x+5)(x−1)=0(x + 5)(x - 1) = 0
  2. Apply the zero product property
    x+5=0orx−1=0x + 5 = 0 \quad \text{or} \quad x - 1 = 0
  3. Solve for x
    x=−5orx=1x = -5 \quad \text{or} \quad x = 1

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