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The sum of three consecutive integers is 72. What are they?

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Answer
23,24,25\boxed{23, 24, 25}

Checking the result, 23+24+25=7223 + 24 + 25 = 72, which confirms our solution is correct.

Problem: Find three consecutive integers whose sum is 7272.

Steps

  1. Define variables
    Let the first integer be xx, the second be x+1x + 1, and the third be x+2x + 2.
  2. Set up the equation
    x+(x+1)+(x+2)=72x + (x + 1) + (x + 2) = 72
  3. Combine like terms
    3x+3=723x + 3 = 72
  4. Subtract 3 from both sides
    3x=693x = 69
  5. Divide both sides by 3
    x=23x = 23
  6. Find the other two integers
    x+1=24,x+2=25x + 1 = 24, \quad x + 2 = 25

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