Find the mean, median and mode of 4, 8, 15, 16, 23, 42
- Mean: add and divide by 6
- Median: even count, so average the middle two
- Mode: no value repeats
The mean sits above the median because 42 pulls it up. That gap is what "skewed right" means.
Descriptive statistics, probability and counting, with the formula written out.
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Descriptive statistics squeeze a list of numbers into one or two that describe it. The arithmetic is easy; the two things that actually cost marks are choosing between a sample and a population, and deciding whether the mean or the median is the honest summary of a skewed list.
Sort the data first. Half of these become obvious once the list is in order.
Add everything, divide by how many. Sensitive to outliers: one huge value drags it.
The middle value of the sorted list, or the average of the middle two when the count is even. Outliers barely move it, which is why incomes are quoted as medians.
The most frequent value. A list can have several modes, or none at all.
Average the squared distances from the mean, then square-root it. Divide by n for a whole population, by n − 1 for a sample. That single choice changes the answer.
Favourable outcomes over total outcomes, when outcomes are equally likely. List the sample space when it is small enough; two dice have 36 outcomes, not 11.
Order matters means permutations, nPr. Order does not matter means combinations, nCr = n! / (r!(n − r)!).
Each one is solved the way the solver solves it: the rule first, then the line.
The mean sits above the median because 42 pulls it up. That gap is what "skewed right" means.
Seven is the most likely total precisely because it has the most ways of happening.
A sample standard deviation divides by n − 1. With small data sets the two answers differ noticeably, and the question usually tells you which one it wants.
The median is the middle of the ordered list. Taking the middle of the list as written is a different number entirely.
Two dice have 36 outcomes, not 11 totals. Each total needs its own count of the ways it can happen.
Add every value and divide by how many there are. For 4, 8, 8, 15, 21 the total is 56 and there are 5 values, so the mean is 11.2. The mean does not have to be one of the values.
The middle value once the numbers are in order. For 4, 8, 8, 15, 21 it is 8. With an even count, take the mean of the middle two. The median ignores outliers, which the mean cannot.
Find the mean, subtract it from each value and square the result, average those squares, then take the square root. Divide by n for a whole population and by n − 1 for a sample.
The mean is the average, the median is the middle, and the mode is the most frequent value. A skewed data set pulls the mean away from the median, which is why house prices are usually quoted as medians.
Divide the number of favourable outcomes by the total number of equally likely outcomes. Drawing a red ball from 3 red and 5 blue is 3/8. Probabilities always fall between 0 and 1.
How many standard deviations a value sits from the mean: z = (x − mean) / standard deviation. A z of 2 means the value is two standard deviations above average.
When the data is a sample standing in for a larger population. Dividing by n − 1 corrects the tendency of a sample to understate the true spread; use n only when you have the whole population.
Yes. Every step is written out, including the squared deviations, so you can check any single number rather than trusting the total.