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Find the derivative of tan(x)

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Answer
sec2(x)\boxed{\sec^2(x)}

Checking this result with standard derivative tables confirms that the derivative of tan(x)\tan(x) is indeed sec2(x)\sec^2(x).

Problem: Find the derivative of tan(x)\tan(x).

Steps

  1. Rewrite as a quotient
    ddx(sin(x)cos(x))\frac{d}{dx} \left( \frac{\sin(x)}{\cos(x)} \right)
  2. Apply the quotient rule
    cos(x)ddx(sin(x))sin(x)ddx(cos(x))(cos(x))2\frac{\cos(x) \cdot \frac{d}{dx}(\sin(x)) - \sin(x) \cdot \frac{d}{dx}(\cos(x))}{(\cos(x))^2}
  3. Evaluate the derivatives of sine and cosine
    cos(x)cos(x)sin(x)(sin(x))cos2(x)\frac{\cos(x) \cdot \cos(x) - \sin(x) \cdot (-\sin(x))}{\cos^2(x)}
  4. Simplify the numerator
    cos2(x)+sin2(x)cos2(x)\frac{\cos^2(x) + \sin^2(x)}{\cos^2(x)}
  5. Apply the Pythagorean trigonometric identity
    1cos2(x)\frac{1}{\cos^2(x)}
  6. Rewrite using reciprocal trigonometric identities
    sec2(x)\sec^2(x)

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