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Find the limit as x approaches infinity of (3x^2 + 2x)/(5x^2 - 1)

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Answer
35\boxed{\frac{3}{5}}

Substituting large values for xx confirms that the ratio of the leading terms dominates, approaching 3/5=0.63/5 = 0.6.

Problem: Find the limit limx3x2+2x5x21\lim_{x \to \infty} \frac{3x^2 + 2x}{5x^2 - 1}.

Steps

  1. Divide numerator and denominator by highest power of x
    limx3x2x2+2xx25x2x21x2\lim_{x \to \infty} \frac{\frac{3x^2}{x^2} + \frac{2x}{x^2}}{\frac{5x^2}{x^2} - \frac{1}{x^2}}
  2. Simplify the fractions
    limx3+2x51x2\lim_{x \to \infty} \frac{3 + \frac{2}{x}}{5 - \frac{1}{x^2}}
  3. Apply the limit as x approaches infinity
    3+050\frac{3 + 0}{5 - 0}
  4. Simplify the result
    35\frac{3}{5}

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