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Solve sqrt(2x + 3) = x

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Answer
x=3\boxed{x = 3}

Substituting x=3x = 3 back into the original equation gives 9=3\sqrt{9} = 3, which is a true statement, while x=1x = -1 is extraneous due to the square root function yielding only non-negative principal roots.

Problem: Solve the radical equation 2x+3=x\sqrt{2x + 3} = x.

Steps

  1. Square both sides
    2x+3=x22x + 3 = x^2
  2. Rearrange into standard quadratic form
    x22x3=0x^2 - 2x - 3 = 0
  3. Factor the quadratic equation
    (x3)(x+1)=0(x - 3)(x + 1) = 0
  4. Solve for xx
    x=3orx=1x = 3 \quad \text{or} \quad x = -1
  5. Check solutions in the original equation
    For x=3:2(3)+3=9=3 (Valid)\text{For } x = 3: \sqrt{2(3) + 3} = \sqrt{9} = 3 \text{ (Valid)}
    For x=1:2(1)+3=1=11 (Extraneous)\text{For } x = -1: \sqrt{2(-1) + 3} = \sqrt{1} = 1 \neq -1 \text{ (Extraneous)}

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