Solve the inequality -3x + 7 <= 1

Answer

\boxed{x \ge 2 \text{ (or } [2, \infty))}

Checking the result, substituting $x = 2$ gives $-3(2) + 7 = 1$ , which satisfies the equation, and choosing $x = 3$ gives $-3(3) + 7 = -2 \le 1$ , which satisfies the inequality.

Problem: Solve the inequality $-3x + 7 \le 1$ .

Steps

Subtract 7 from both sides $-3x \le 1 - 7$
Simplify the right side $-3x \le -6$
Divide both sides by -3 and reverse the inequality sign $x \ge \frac{-6}{-3}$
Simplify the fraction $x \ge 2$

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