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Solve x^2 - 6x + 2 = 0 by completing the square

Worked through step by step. More quadratics.

Answer
x=3±7\boxed{x = 3 \pm \sqrt{7}}

Substituting these values back into the original equation confirms they satisfy x2−6x+2=0x^2 - 6x + 2 = 0.

Problem: Solve x2−6x+2=0x^2 - 6x + 2 = 0 by completing the square.

Steps

  1. Subtract 2 from both sides
    x2−6x=−2x^2 - 6x = -2
  2. Add the square of half the coefficient of xx to both sides
    x2−6x+9=−2+9x^2 - 6x + 9 = -2 + 9
  3. Factor the left side and simplify the right side
    (x−3)2=7(x - 3)^2 = 7
  4. Take the square root of both sides
    x−3=±7x - 3 = \pm\sqrt{7}
  5. Add 3 to both sides
    x=3±7x = 3 \pm\sqrt{7}

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