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How many permutations of 5 items taken 2 at a time?

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Answer
20\boxed{20}

Checking with the multiplication principle, there are 5 choices for the first item and 4 remaining choices for the second, giving 5×4=205 \times 4 = 20.

Problem: Find the number of permutations of 5 items taken 2 at a time, denoted as P(5,2)P(5, 2) or 5P2^{5}P_{2}.

Steps

  1. Apply the permutation formula
    P(n,r)=n!(nr)!P(n, r) = \frac{n!}{(n-r)!}
  2. Substitute n=5n = 5 and r=2r = 2
    P(5,2)=5!(52)!P(5, 2) = \frac{5!}{(5-2)!}
  3. Simplify the denominator
    P(5,2)=5!3!P(5, 2) = \frac{5!}{3!}
  4. Expand the factorials
    P(5,2)=5×4×3!3!P(5, 2) = \frac{5 \times 4 \times 3!}{3!}
  5. Cancel the common term 3!3!
    P(5,2)=5×4P(5, 2) = 5 \times 4
  6. Multiply
    P(5,2)=20P(5, 2) = 20

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