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Solve 2x^2 - 4x - 3 = 0

Worked through step by step. More quadratics.

Answer
x=2±102\boxed{x = \frac{2 \pm \sqrt{10}}{2}}

Substituting these exact values back into the original equation confirms they satisfy 2x24x3=02x^2 - 4x - 3 = 0 (approx. x2.581x \approx 2.581 or x0.581x \approx -0.581).

Problem: Solve the quadratic equation 2x24x3=02x^2 - 4x - 3 = 0.

Steps

  1. Identify coefficients
    a=2, b=4, c=3a = 2, \ b = -4, \ c = -3
  2. Apply the quadratic formula
    x=(4)±(4)24(2)(3)2(2)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-3)}}{2(2)}
  3. Simplify the discriminant and denominator
    x=4±16+244x = \frac{4 \pm \sqrt{16 + 24}}{4}
  4. Simplify the square root
    x=4±404x = \frac{4 \pm \sqrt{40}}{4}
  5. Reduce the radical
    x=4±2104x = \frac{4 \pm 2\sqrt{10}}{4}
  6. Divide numerator and denominator by 2
    x=2±102x = \frac{2 \pm \sqrt{10}}{2}

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