SolveMathAI

Solve 2x^2 - 4x - 3 = 0

Worked through step by step. More quadratics.

Answer
x=2±102\boxed{x = \frac{2 \pm \sqrt{10}}{2}}

Substituting these exact values back into the original equation confirms they satisfy 2x2−4x−3=02x^2 - 4x - 3 = 0 (approx. x≈2.581x \approx 2.581 or x≈−0.581x \approx -0.581).

Problem: Solve the quadratic equation 2x2−4x−3=02x^2 - 4x - 3 = 0.

Steps

  1. Identify coefficients
    a=2, b=−4, c=−3a = 2, \ b = -4, \ c = -3
  2. Apply the quadratic formula
    x=−(−4)±(−4)2−4(2)(−3)2(2)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-3)}}{2(2)}
  3. Simplify the discriminant and denominator
    x=4±16+244x = \frac{4 \pm \sqrt{16 + 24}}{4}
  4. Simplify the square root
    x=4±404x = \frac{4 \pm \sqrt{40}}{4}
  5. Reduce the radical
    x=4±2104x = \frac{4 \pm 2\sqrt{10}}{4}
  6. Divide numerator and denominator by 2
    x=2±102x = \frac{2 \pm \sqrt{10}}{2}

Generated by SolveMath AI and kept here so the next person asking gets it instantly. AI can make mistakes, so check anything that matters.

Solve your own

Same solver, same steps, no account.

Enter to solve · Shift+Enter for a new line

  • Free
  • No account
  • Every step shown
  • Arithmetic to calculus

More solved problems

Quadratics solver →